Write the equation, in slope-intercept form, of the line passing through the origin and the point (-4,3) .

Guest Jul 9, 2019

#1**+3 **

Using the information that the line passes through the points (0, 0) and (-4, 3) , we can find the slope.

slope = \(\frac{\text{rise}}{\text{run}}\ =\ \frac{y_2-y_1}{x_2-x_1}\ =\ \frac{3-0}{-4-0}\ =\ -\frac34\)

Using the point (0, 0) and the slope -\(\frac34\) , the equation of the line in point-slope form is

y - 0 = -\(\frac34\)(x - 0)

Simplify both sides of the equation to get

y = -\(\frac34\)x

hectictar Jul 9, 2019

#1**+3 **

Best Answer

Using the information that the line passes through the points (0, 0) and (-4, 3) , we can find the slope.

slope = \(\frac{\text{rise}}{\text{run}}\ =\ \frac{y_2-y_1}{x_2-x_1}\ =\ \frac{3-0}{-4-0}\ =\ -\frac34\)

Using the point (0, 0) and the slope -\(\frac34\) , the equation of the line in point-slope form is

y - 0 = -\(\frac34\)(x - 0)

Simplify both sides of the equation to get

y = -\(\frac34\)x

hectictar Jul 9, 2019