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72
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Amy and Belinda each roll a sheet of 6-inch by 8-inch paper to form a cylindrical tube. Amy tapes the two 8-inch sides together without overlap. Belinda tapes the two 6-inch sides together without overlap. What is  times the positive difference of the volumes of the two tubes?

 Mar 13, 2021
 #1
avatar+311 
0

8 inch paper will be x

 

6 inch paper will be y

 

The height for x is 8, and the circumference is 6

 

6/pi=1.90985932

 

1.90985932/2=0.95492966

 

x≈22.92

The height for y is 6, and the circumference is 8

 

8/pi=2.54647909

 

2.54647909/2=1.27323955

 

y≈30.56

 

22.92+30.56=53.48

 

Then just multiply whatever number you put in that blank space and there you go!

 

Yay!

 Mar 13, 2021
 #2
avatar+118069 
+1

Radius  of Amy's cylinder  =   6/(2pi ) =  3/pi

Height of Amy's cylinder =  8

 

Radius of Belinda's cylinder = 8/(2pi)  = 4/pi

Height of  Belinda's cylinder  = 6

 

 

Volume  of  Amy's  cylinder =   pi  ( 3/pi)^2 ( 8)  =  72/pi

Volume of Belinda's cylinder =  pi ( 4/pi)^2  ( 6)  96/pi

 

Positve difference  between  the volumes  =   (96  - 72)   / pi   =   24 /  pi

 

 

cool cool cool

 Mar 13, 2021
edited by CPhill  Mar 13, 2021
edited by CPhill  Mar 13, 2021
 #3
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0

thank you!

Guest Mar 13, 2021

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