Help can anyone solve this? Im sure that there are some ingeniousness people here.

First let's draw two lines perpendicular to the base, forming two right triangles, like this...

Now we can find  h  and  x  .

sin 60°  =  h / 2          so          h   =   2 sin 60°   =   √3

cos 60°  =  x / 2          so          x   =   2 cos 60°   =   1

So...

the height of the trapezoid   =   √3   ,

the first base   =   2  ,   and

the second base   =   2 + 1 + 1  =  4

area of trapezoid  =  (first base + second base)/2  *  height

area of trapezoid  =  (2 + 4)/2  *  √3

area of trapezoid  =  3√3    sq. units