In an equation of the form k = ax^2 + bx + c with a > 0, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x + 12)(x - 8), what is the least possible value for k?
Very much apprecited.
k = (6x + 12)(x - 8) expand this
k = 6x^2 + 12x - 48x - 96
k = 6x^2 - 36x - 96
The minimum value for k occurs at x = - [ -36] / [ 2 * 6 ] = 36 /12 = 3
So....the minimum value of k is
6(3)^2 - 36(3) - 96 =
54 - 108 - 96 =
-54 - 96 =
-150
