why cosx-sin2x will yiled two values for x, i.e. x=pi/2 or x=pi/6 , how pi/6 and pi/2 come out?by what method?
Hello Guest!
cosx - sin2x = 0
sin2x = 2 sinx cosx
cosx - 2 sinx cosx = 0
cosx * (1 - 2 sinx) = 0
cosx = 0
x1 = arc cos 0
x1 = pi / 2
x2 = 3 pi / 2
1 - 2 sinx = 0
2 sinx = 1
sin x = 0.5
x = arc sin 0.5
x3 = pi / 6
x4 = 2 pi / 6
Greeting asinus :- )
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x4 = 2 pi / 6 is not correct !
x4 = arc sin 0.5 = 5 pi / 6
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