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Use technology or a z-score table to answer the question.

The weights of logs in a wood pile are normally distributed with a mean of 17 pounds and a standard deviation of 3.4 pounds. The wood pile is composed of 325 logs.

How many of the logs will weigh 15 pounds or more? 

 

I tried using the z-score formula 325-17

                                                      —      =90.588 , this is not a possible answer since 90 is not on the z score table. Can you help me?

                                                      3.4

 Apr 19, 2019
 #1
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Mmmm....you got it a little messed up....we want to find the %  that matches this computed z score

 

[ 15 - 17 ] / 3.4  =  -.59

 

Look at the z score table for  -.59   and you have ≈ .2776

 

So.....the number of logs weighing  more  than 15 lbs.  is

 

[ 1 - .2776 ] (325)  =

 

about  235 logs 

 

cool cool cool

 Apr 20, 2019

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