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A diver jumps from a platform 15 meters above the surface of the water. The diver's height, in meters, above the water is given by the equation h(t)=-4.9t^2 + 8.5t + 15 where t is the time in seconds after the diver jumps. What is the max height of the diver and how long does it take the diver to reach that height?

 Jan 30, 2021

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Max height occurs at  t = -b/2a      =    -8.5/(2 * -4.9)   = .8673 seconds

Height will be      -4.9(.86732) + 8.5(.8673) + 15 = ........... meters above the water

 Jan 30, 2021
 #1
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+1
Best Answer

Max height occurs at  t = -b/2a      =    -8.5/(2 * -4.9)   = .8673 seconds

Height will be      -4.9(.86732) + 8.5(.8673) + 15 = ........... meters above the water

Guest Jan 30, 2021

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