Let d and q be the roots of the quadratic equation x^2 + 6x - 4 = 0. Find the value of 2d^2 + 2q^2.
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\( x^2 + 6x - 4 = 0\\ x=-3\pm \sqrt{9+4}\\ \color{blue}x=-3\pm\sqrt{13}\)
\(d=0.60555\\ q=-6.60555\)
\(2d^2+2q^2=88\)
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