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If $s-x=3$ and $s^{2} + x^{2} = 29$, what is the value of sx?

 Jan 27, 2021

Best Answer 

 #1
avatar+425 
+1

(s - x)(s - x) = s^2 + x^2 - 2sx 

We know some of the values so we can plug stuff in. 

(3)(3) = 29- 2sx 

9 = 29 - 2sx

2sx = 20

sx = 10

 

I hope this helped. :)))

=^._.^=

 Jan 27, 2021
 #1
avatar+425 
+1
Best Answer

(s - x)(s - x) = s^2 + x^2 - 2sx 

We know some of the values so we can plug stuff in. 

(3)(3) = 29- 2sx 

9 = 29 - 2sx

2sx = 20

sx = 10

 

I hope this helped. :)))

=^._.^=

catmg Jan 27, 2021
 #2
avatar+116126 
0

Very nice, catmg  !!!!

 

 

cool cool cool

CPhill  Jan 27, 2021
 #3
avatar
0

Good work, catmg !   laugh

Guest Jan 27, 2021
 #4
avatar+425 
+1

Awww, thank you. :D

 

=^._.^=

catmg  Jan 27, 2021

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