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 A rock is thrown upward from the height of 5 ft with an initial velocity of 50 ft per second. The height h(in feet) of the rock at time t seconds is h(t)=-16t^2+50t+5. When will the ball reach a height of 8 ft?

 Jan 31, 2021
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YOU THROW A ROCK, BUT ASK WHEN THE BALL REACHES 8 FT?   oops!

 

 

8 = -16t^2 + 50t+5 

0 = -16t^2 + 50t -3       Quadratic formula shows t =0.0611985     OR   3.0638 SECONDS   

      (One is for thr rock-ball on the way up...the other on the way down)

 Jan 31, 2021

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