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Suppose that x, y, z \($x \le y \le z$\)  are positive integers satisfying , and such that the product of all three numbers is twice their sum. What is the sum of all possible values of z?

 

i already came up with one pair that supports \(x \le y \le z\), 2,2,4. 4 being z, and the solution isn't 4

 Jun 25, 2020
 #1
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I found the following 3 solutions:

 

x          y          z

1          3         8

1          4         5

2         2         4

So, z =8 + 5 + 4 = 17

 Jun 25, 2020

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