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In a certain country, the probability that a baby that is born is a boy is 0.52 and the probability that a baby that is born is a girl is 0.48. A family has two children. If X is the number of girls born to a family, find the probability that the family has 0, 1, or 2 girls.

 

Create the binomial distribution table for P (X).

 Apr 15, 2019
 #1
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P(0 girls)  = (.52)^2  ≈ .27

P(1 girl )   = 2C1 * (.52)(.48) ≈ .50

P(2 girls)  = (.48)^2   ≈ .23

 

cool cool cool

 Apr 15, 2019
 #2
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2C1 * (.52)(.48) ≈ .50

 

is that a C before the 2 and after the 1?

Guest Apr 15, 2019

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