Find the radius of the circle inscribed in triangle $ABC$ if $AB = 5$, $AC = 6$, and $BC = 8$.
Inradius = Area / Semi-perimeter
Semi-perimeter = ( 5 + 6 + 8) / 2 = 19 / 2 = 9.5
Area = sqrt [ 9.5 ( 9.5 - 5) (9.5 -6) (9.5 - 8) ] ≈ 14.9812
Inradius = 14.9812 / 9.5 ≈ 1.58
+1348 
