x = 3cosθ + 2 y = 2sinθ - 1
x - 2 = 3cosθ y + 1 = 2sinθ
cos θ = (x - 2) / 3 sin θ = (y + 1) / 2
And sin^2θ + cos^2θ = 1
So
(x - 2)^2 (y + 1)^2
_______ + _________ = 1
9 4
This is an ellipse centered at ( 2, -1)
x is on the interval ( 2 - sqrt 9 , 2 + sqrt 9) = ( -1 , 5)