+1859 Triangle $ABC$ has vertices $A(2, 3),$ $B(1, -8)$ and $C(-3, 2).$ The line containing the altitude through $A$ intersects the point $(0, y).$ What is the value of $y$?
+129771 We can find an equation of the line through B and C
The slope of this line is [ 2 - - 8 ] / [ -3 -1 ] = 10 / -4 = -5/2
The equation of the line through A will have a negative reciprocal slope = 2/5
So.....the equation of this line is
y = (2/5)(x-2) + 3
y = (2/5)x - 4/5 + 3
y = (2/5)x +11/5
When x = 0 , y = 11/5 = 2.2
