Find the area of the region satisfying the inequality x^2 + y^2 <= 4x + 6y+13 - 2x + 3y + 9.
This will be the area inside of a circle...first simplify to
x^2 -2x + y^2-9y = 22 then complete the square for x and y
(x-1)^2 + (y-4.5)^2 = 22 + 1 + 20.25
= 43.25 43.25 is the radius squared
area = pi r^2 = 43.25 π