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In how many ways can the digits of 48,008 be arranged to form a 5-digit number? (Remember, numbers cannot begin with 0.)

 Jan 6, 2021
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So for the beginning number we have 3 possibilities and the second number have 4 possibilities, the 3rd one have 3, the 4th one have 2, and there is only one possibility for 5, so there is 3*4! arrangements, however, since there is two 8s and two 0s, we have to divide by 2!*2!, which gets the final answer of 18. Hope this helped :)

 Jan 6, 2021
edited by TC072  Jan 6, 2021

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