In how many ways can the digits of 48,008 be arranged to form a 5-digit number? (Remember, numbers cannot begin with 0.)

Guest Jan 6, 2021

#1**+1 **

So for the beginning number we have 3 possibilities and the second number have 4 possibilities, the 3rd one have 3, the 4th one have 2, and there is only one possibility for 5, so there is 3*4! arrangements, however, since there is two 8s and two 0s, we have to divide by 2!*2!, which gets the final answer of 18. Hope this helped :)

TC072 Jan 6, 2021