A standard six-sided die is rolled 6 times. You are told that among the rolls, there was one 1, two 2's, one 3, and two 4's. How many possible sequences of rolls could there have been?
permutations of {1, 2, 2, 3, 4, 4} ==6!/(2!)(2!)==720 / 4 ==180 sequences of rolls
+313 we can make it simple from an example like if we toss a coin we can get 2 possible outcome
if
we toss 2 coin we can get 2 * 2 possible outcome
if we toss 3 coin we can get 2* 2 *2 possible outcomes
so tossing a dice 6 times is same as tossing 6 dice one time.
for one fair dice the possible no of outcome is 6 {1,2,3,4,5,6}
for 2 dice possible outcomes 6*6
for 3 dice possible outcomes 6*6 *6
for 4 dice possible outcomes 6*6*6*6
for 5 dice possible outcomes 6*6*6*6*6
for 6 dice possible outcomes 6*6*6*6*6*6 = 6 ^6 [answer]
