5(x+4)-8=x+32
What I have got:
I know you have to ditrubute 5 into the parenthces
5x+20-8=32+x
then i add 8 to both sides
5x+20=32+x
but i can't get x to be isloated.
After you distributed, you got:
5x + 20 - 8 = 32 + x (This is correct!)
Look at the left side: you have + 20 - 8; combine these to get 12:
5x + 12 = 32 + x
You need to get all the x-terms to one side; you can get rid of the x-term on the right side by subtracting x from both sides:
4x + 12 = 32
Can you finish it from here?
After you distributed, you got:
5x + 20 - 8 = 32 + x (This is correct!)
Look at the left side: you have + 20 - 8; combine these to get 12:
5x + 12 = 32 + x
You need to get all the x-terms to one side; you can get rid of the x-term on the right side by subtracting x from both sides:
4x + 12 = 32
Can you finish it from here?