Im having trouble with this
One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab = 72. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)
solve each equation for a, then set them = to each other and solve for B
a= 48/b^4
a=72/b
48/b^4 = 72/b
48/b^3=72
1/b^3=3/2
b^3=2/3
cuberoot b^3 = Cuberoot (2/3)
b= (2/3)^1/3
b= .87
