Let f(x) = \left\lfloor\frac{3x - 5}{3x + 4}\right\rfloor. Evaluate f(1)+f(2) + f(3) + \dots + f(999)+f(1000). (This sum has $1000$ terms, one for the result when we input each integer from $1$ to $1000$ into $f$.)
f(1) = -1
f(2) = 0
...
f(1000) = 0
Sum = -1
+1234 
