In the diagram below, PQRS is a parallelogram with a perimeter of 26 and an area of 28. What is the perimeter of rectangle OSTQ? Include an explanation of how you solved the problem.
+137 28
Explanation:
In order to solve this problem we need to find out what $QR$ is.
We know that the perimeter of the parallelogram was given as $24$ and that two of the sides were given as $5$. $5+5=10$ $24-10=14/2=7$. Now we know that the base was $7$.
We can find the height by taking the area that they gave us and dividing that by $7$. We get $4$.
Since we now know that the height of the parallelogram is $4$ that means $OQ$ is also $4$.
Next we need to find what $RT$ is.
$4^2+B^2=5^2$.
Since we now $5^2$ is $25$ and that $4^2$ is $16$, we can use the following equation.
$25-16=9$. $\sqrt{9}=3$.
Now we know that $RT$ is $3$ we can start adding the sides.
$7+3=10+4=14 \cdot 2=28$.
[b]The perimeter of the rectangle $QOST$ is 28![/b]
