In acute triangle ABC, angle A = 62 degrees . Let O be the circumcenter of triangle ABC. Find angle OBC , in degrees.
Then angle BAC = 62°......but angle BOC is a central angle intercepting the same arc as BAC.....therefore, its measure is 2*BAC = 124°
So in triangle BOC.....angle BOC = 124° and OB and OC are equal radii
Therefore angle OBC = angle OCB = (180 -124) / 2 = 56 / 2 = 28°