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If I have a triangle that has an area of 196 and the base of the triangle is one half of its height. How would I find its base and height?

 Apr 6, 2016
 #1
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Area of a triangle =   base * height/2 = b* h/2

 

In this case, b = 1/2 h    or,   put another way........2b = h

 

So   .....substituting this into the area "formula".....we have.....

 

196  = b*h /2  =   b[2b]/ 2   = [2b*b]/2  = b^2

 

196  = b^2       take the square root of both sides

 

14  = base    and the height is twice this  = 28

 

 

cool cool cool

 Apr 6, 2016
 #2
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+5

Height=h

Base =h/2

Area= [Base x Height] /2

Area=28 x 14=392/2=196 Sq. units.

 

Solve for h:

h^2/4 = 196

Multiply both sides by 4:

h^2 = 784

Take the square root of both sides:

Answer: | h = 28        and        Base=28/2=14

 Apr 6, 2016
 #3
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0

Ty for your help.

 Apr 6, 2016

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