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In the diagram below, AM = BM = CM and angle BMC + angle A = 201 degrees. Find angle B in degrees.

 

 Aug 7, 2021
 #1
avatar+76 
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BMC + A = 201

BMC + CMA = 180

BMC + C also = 201

 

3BMC + CMA + C +A = 582, and we know CMA + C + A = 180, so 3BMC = 582-180 = 402, and thus BMC = 134

 

B = MCB, and finish the last step to get B

 Aug 8, 2021
 #3
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Related posts: https://web2.0calc.com/questions/help-geometry_140#r6

Nomination for the Fields MeTal: Category: Mind Numbingly Atrocious

Guest Aug 27, 2021
 #2
avatar+114511 
+1

Let's see

angle BMC +angle A = 201

 

consider triangle CMA

2

2A=201-A

3A=201

A=67 degrees

so

angle CMA= 180-2*67 = 46degrees

 

so angle B = half of 46 = 23 degrees.

 

I have not carefully checked this.

 Aug 22, 2021

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