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In triangle $ABC,$ $AB = 15,$ $BC = 10,$ and $AC = 12.$ Find the length of the shortest altitude in this triangle.

 Jun 4, 2024
 #1
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Find the area using Heron's Formula

 

A =  sqrt [ 18.5 (3.5) (6.5) (8.5) ]    ≈  59.8

 

The shortest altitude is drawn to the longest side

 

59.8 =  (1/2) (15) (altitude)

 

59.8 / [ 15/2 ] =  altitude   ≈  7.97  

 

cool cool cool

 Jun 4, 2024

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