In the diagram, $\overline{CX}$ bisects $\angle ACB$. Find the ratio of the area of triangle $BCX$ to the area of triangle $ACX$. Express your answer as a common fraction.
Since CX is an angle bisector
AX / AC = BX / BC
AX /10 = BX / 10
AX / BX = 10 / 10
AX / BX = 1 / 1
So triangle ACX and BCX have the same bases...and they are under the sameheight
So the ratios of their areas = 1/1
+819 
