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In the diagram, $\overline{CX}$ bisects $\angle ACB$.  Find the ratio of the area of triangle $BCX$ to the area of triangle $ACX$.  Express your answer as a common fraction.

 

 Oct 13, 2023
 #1
avatar+128732 
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Since CX is an angle bisector

 

AX / AC  =  BX / BC

AX /10  = BX / 10

AX / BX  = 10 / 10

AX / BX  =  1 / 1

 

So  triangle ACX and BCX have the same  bases...and they are under the sameheight

 

So  the ratios of their areas =  1/1

 

cool cool cool

 Oct 13, 2023

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