In the diagram, $\overline{CX}$ bisects $\angle ACB$. Find the ratio of the area of triangle $BCX$ to the area of triangle $ACX$. Express your answer as a common fraction.

Since CX is an angle bisector

AX / AC = BX / BC

AX /10 = BX / 10

AX / BX = 10 / 10

AX / BX = 1 / 1

So triangle ACX and BCX have the same bases...and they are under the sameheight

So the ratios of their areas = 1/1