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ABCD is a square of side length 1, and M and N are the midpoints of sides AB and BC, respectively.  AN  and CM intersect at P.  Find the area of quadrialteral APCB..

 Dec 6, 2020

Best Answer 

 #2
avatar+846 
+2

AQ = (√2)/2

 

∠BAN = tan-1(1/2) 

 

∠PAQ = 45º - ∠BAN 

 

PQ = tan∠PAQ * AQ 

 

Area of quadrilateral APCB = 1/3 units2 smiley

 

 Dec 7, 2020
edited by jugoslav  Dec 7, 2020
 #1
avatar+114221 
+1

*******

 

cool cool cool

.
 Dec 6, 2020
edited by CPhill  Dec 7, 2020
 #3
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You have an error there. That area cannot be larger than 1 half of the square's area!!!

Guest Dec 7, 2020
 #2
avatar+846 
+2
Best Answer

AQ = (√2)/2

 

∠BAN = tan-1(1/2) 

 

∠PAQ = 45º - ∠BAN 

 

PQ = tan∠PAQ * AQ 

 

Area of quadrilateral APCB = 1/3 units2 smiley

 

jugoslav Dec 7, 2020
edited by jugoslav  Dec 7, 2020

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