help with graphing

The graph of y = f(x) is a parabola whose vertex is at (1, -2). The graph of y = f(x) - 3 is also a parabola. Where is the vertex of the graph of y = f(x) - 3?

Hello Guest!

$y_1=f(x) =( x-{\color{BrickRed}1})^2{\color{BrickRed}-2}\ |\ \color{blue}vertex\ (1,-2)\\ \color{blue}y_1=f(x)=x^2-2x-1$

$y_2=f(x)-3 =( x-1)^2-2\color{blue}-3$

$y_2=f(x)-3 =( x-{\color{BrickRed}1})^2{\color{BrickRed} -5}\ |\ \color{blue}vertex\ (1,-5)\\ \color{blue}y_2=f(x)=x^2-2x-4$

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