Three integers are chosen at random without replacement from the first 20 positive integers. What is the probability that their product is even?
+33652 For the product to be even there must be at least one even integer.
Probability of no even integers p0 = (10/20)*(9/19)*(8/18)
Hence probability of at least one even integer = probability of even product p = 1 - (10/20)*(9/19)*(8/18)
(Edited to make more sense! Thanks EP).
