The ratio of two numbers is 3:5. When 4 is subtracted from the lesser of the two numbers and 8 is added to the larger of the two, the new ratio is 2:7. What is the greater of the two numbers before 8 is added to it?

I decided to make the smaller number x and the larger number y. Here is what I have, x:y = 3:5 and x-4:y+8=2:7.

I do not know what to do after this. CAn someone help explain? I do not want answers.

Guest May 13, 2020

#1**+1 **

Let the smaller number = x and the greater = y

We know that

x / y = 3/5 ⇒ x = (3/5)y (1)

And we know that

[ x - 4] 2

______ = ___

[y + 8] 7

Sub (1) into this for x

[ (3/5)y - 4 ] 2

_________ = ___

[ y + 8] 7

Cross-multiply and you have

7 [ (3/5)y - 4 ] = 2 [ y + 8]

You should be able to solve it now for the larger number, y

CPhill May 14, 2020