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What is the equation of the line perpendicular to 2x - 3y = 13 that passes through the point (-6,5)?

 Sep 17, 2020
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Slope, m , of given line = 2/3     perpindicular slope = - 1/m = -3/2

y-5 = -3/2 (x+6)       re-arrange to y=mx + b form to find correct answer 

 Sep 17, 2020
edited by ElectricPavlov  Sep 17, 2020

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