Ryan had some blue and green buttons. 3/7 of the buttons are blue and the rest were green. He gave away 2/5 of his buttons. 80 of the buttons given away were blue. 2/3 of the buttons left were green. How many buttons did Ryan have altogether at first?

Guest Jun 6, 2021

#1**+2 **

Ryan had some blue and green buttons. 3/7 of the buttons are blue and the rest were green. He gave away 2/5 of his buttons. 80 of the buttons given away were blue. 2/3 of the buttons left were green. How many buttons did Ryan have altogether at first?

(3/7) are blue (4/7) are green....let N be the total

No.remaining = blue remaining + green remaining

(3/5)N = [(3/7)N -80 ] + (2/3) (N - (2/5)N) simplify

(3/5)N = (3/7)N - 80 + (2/3)N - (4/15)N

(3/5)N = (3/7)N - 80 + (10/15)N - (4/15)N

(3/5)N = (3/7)N - 80 + (2/5)N

80 = (3/7)N + (2/5)N - (3/5)N

80 = (3/7)N - (1/5)N 7

80 = (15/35) - (7/35)N

80 = (8/35) N

N = 80 (35/8) = 350

CPhill Jun 6, 2021