Consider the matrices
\(A\) is the matrix \(( \begin{matrix} 4 & -2\\2& 4\end{matrix})\)
\(B\) is the matrix that rotates vectors by \(\pi/12\) counterclockwise\(\)
Solve the equation: \(B^8X=A\) for the matrix \(X\)\(\)
$X = \begin{pmatrix} -1 + \sqrt{3} & 2 \\ -2 & \sqrt{3} -1 \end{pmatrix}$
