Help with period and horizontal translation

y=10sin(1π/9*θ+4π0)-17 I need help with finding the period and horizontal translation, whats the formula?

Is this what you intended?    4pi*0 was rather strange = it equals zero.   ://

\(y=10sin(\frac{\pi\theta}{9}+4π*0)-17\\ y=10sin(\frac{\pi}{9}\theta)-17\\ Period=2\pi\div \frac{\pi}{9}\\ Period=2\pi\times \frac{9}{\pi}\\ Period=18\\ Amplitude =10\\ \mbox{horizontal translation is 17 units down } \)

Here is the graph

https://www.desmos.com/calculator/pyyueb6y5h

I think the function you are asking about is this one:

y = 10 sin [ (pi/9 +4pi) θ ] - 17

Melody's answer for the horizontal translation is correct.....

For the period.....we need to solve this for  "x"

[ pi/9 + 4pi]* x  = 2pi        .......divide through by pi

[ 1/9 + 4] * x  = 2

[ 37/9]x = 2     multiply both sides by 9/37

x = 18/37 rads  = about 27.87°

Here's the graph  [in degrees] :  https://www.desmos.com/calculator/unxizoured