permutations there are 6 students and 8 desks how many possible seating arrangements are there? i don't understand how to do it and it's not 8 times 6
+37170 nPr ? I am not sure about this one but 8 p 6 = 20160 Does that SEEM right?
+37170 nPr ? I am not sure about this one but 8 p 6 = 20160 Does that SEEM right?
+23254 Finding the number of seats that will remain empty is a combinations problem because the two empty seats are indistinguishable.
There are two seats that will remain empty. The number of places that this can occur is 8C2 = 28.
Placing the students is a permutations problem because, in this case, order is important.
6P6 = 720.
Putting these two answers together: 28 x 720 = 20,160 ways.
