The coefficient of kinetic friction between a 3.0 kg wooden block and the surface on which it is moving is 0.28. Determine the work required to move the block 12 feet upon this surface.
Ffriction=mgμf=(3)(9.8)(0.28)=8.232N12ft=3.6576mWork=8.232N×3.6576m=30.11Nm=30.11J
Isn'T the force in the work equation the net force. Why are we using the force of friction and not the Force applied?
