You are given a bag with 6 green marbles, 4 blue marbles, 12 yellow marbles, and 10 red marbles. Find the theoretical probability of each random event. (Enter your probabilities as fractions.)
I thought (a) could be 62 but I could be wrong
(a) Drawing a green marble
=_________
(b) Drawing a red marble
=____________
(c) Drawing a marble that is not yellow
=a_____________
any probability is between 0 and 1 so 62 is a non-starter
there are 32 total marbles in the bag
a) \(P[\text{drawing a green marble}] = \dfrac{6}{32}=\dfrac{3}{16}\)
b) \(P[\text{drawing a red marble}] = \dfrac{10}{32}=\dfrac{5}{16}\)
c) The easiest way to do this is find the probability of drawing a yellow marble and subtracting that from 1
\(P[\text{drawing a !yellow marble}] = 1-P[\text{drawing a yellow marble}] = 1 - \dfrac{12}{32} = \dfrac{20}{32} = \dfrac{5}{8}\)
\(62 = \dfrac {62}{1} = \dfrac{124}{2} = \dots \\ \mathbb{Z} \subset \mathbb{Q} \\ \text{so yes 62 is a "fraction", more accurately a rational number}\\ \text{it also happens to be a completely wrong answer in this context but that's another story}\)
.Rom there might be something wrong with your display.
The question was “Does 62 look like a fraction?”
It wasn’t “Can you make 62 look like a fraction?”
I don’t know what the funny-looking Z, sideways U followed by a funny-looking Q means. Is that formula used to turn whole numbers into fractions? If I learn this, will whole numbers start looking like fractions to me?
Maybe the question asker knows that formula.