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You are given a bag with 6 green marbles, 4 blue marbles, 12 yellow marbles, and 10 red marbles. Find the theoretical probability of each random event. (Enter your probabilities as fractions.)

 

I thought (a) could be 62 but I could be wrong

 

(a) Drawing a green marble 
 =_________

(b) Drawing a red marble 
 =____________


(c) Drawing a marble that is not yellow 

=a_____________

Guest Sep 30, 2018
 #1
avatar+3206 
+1

any probability is between 0 and 1 so 62 is a non-starter

 

there are 32 total marbles in the bag

 

a) \(P[\text{drawing a green marble}] = \dfrac{6}{32}=\dfrac{3}{16}\)

 

b) \(P[\text{drawing a red marble}] = \dfrac{10}{32}=\dfrac{5}{16}\)

 

c) The easiest way to do this is find the probability of drawing a yellow marble and subtracting that from 1

 

\(P[\text{drawing a !yellow marble}] = 1-P[\text{drawing a yellow marble}] = 1 - \dfrac{12}{32} = \dfrac{20}{32} = \dfrac{5}{8}\)

Rom  Sep 30, 2018
edited by Rom  Sep 30, 2018
 #2
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Does 62 look like a fraction?

Guest Sep 30, 2018
 #3
avatar+3206 
0

\(62 = \dfrac {62}{1} = \dfrac{124}{2} = \dots \\ \mathbb{Z} \subset \mathbb{Q} \\ \text{so yes 62 is a "fraction", more accurately a rational number}\\ \text{it also happens to be a completely wrong answer in this context but that's another story}\)

Rom  Sep 30, 2018
 #4
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Rom there might be something wrong with your display.

The question was “Does 62 look like a fraction?”

It wasn’t “Can you make 62 look like a fraction?”

 

I don’t know what the funny-looking Z, sideways U followed by a funny-looking Q means. Is that formula used to turn whole numbers into fractions? If I learn this, will whole numbers start looking like fractions to me?

Maybe the question asker knows that formula.

Guest Sep 30, 2018
 #5
avatar+3206 
0

\(\mathbb{Z} \subset \mathbb{Q} \\ \\ \text{simply says that the integers are a subset of the rationals}\)

Rom  Oct 1, 2018

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