Cody buys a soda that offers another soda free if he is lucky. The cap reads '1 in 6 wins!', meaning that each soda has a 1/6 probability of winning. Cody sees this and buys six of these sodas, thinking he is guaranteed a seventh. What is the true probability he will win at least one more soda? Express your answer as decimal to the nearest hundredth.

Guest May 23, 2020

#1**+1 **

I THINK:

he has a 5/6 chance of NOT winning a soda each time

(5/6)^{6} = .335 chance of NOT winning a soda with six purchases

1- .335 = .665 chance of WINNING with a six-pak purchase 66.5%

ElectricPavlov May 23, 2020