The values of x and y are always positive, and x^2 and y vary inversely. If y is 10 when x is 2, then find x when y is 4000.

Guest Sep 6, 2021

#1**+1 **

y = k/x^{2}

x^{2}y= k = 2^{2} *10 = 40

x^{2} y = 40

x^{2} (4000) = 40

x^{2} = 1/100

x = 1/10

ElectricPavlov Sep 6, 2021