Find the set of values of k for which this equation has two real roots.

5x^2 + 4k*x + k = 0

thanks in advance lol

Guest Dec 3, 2020

#1**+1 **

If this equation has two real roots, the discriminant must be > 0

Therefore

(4k)^2 - 4 (5)(x) > 0

16k^2 - 20k > 0

4k ( 4k - 5) > 0

One solution is that k > 5/4

The other solution is k < 0

CPhill Dec 3, 2020

#2**+1 **

Well let's get started, the quadratic equation formula is( -b+-sqrt(b^2-4ac))/2, next, we get

a=5

b=4k

c=k

Next we plug it in,[ -4k +- sqrt(16k^2-20k)]/10, now I cannot give the answer because that is not letting you learn, so you must find the value of 16k^2 - 20k that is greater than 0, > 0. Solve the question and good luck 👍

Guest Dec 3, 2020