Find the set of values of k for which this equation has two real roots.
5x^2 + 4k*x + k = 0
thanks in advance lol
+130511 If this equation has two real roots, the discriminant must be > 0
Therefore
(4k)^2 - 4 (5)(x) > 0
16k^2 - 20k > 0
4k ( 4k - 5) > 0
One solution is that k > 5/4
The other solution is k < 0
Well let's get started, the quadratic equation formula is( -b+-sqrt(b^2-4ac))/2, next, we get
a=5
b=4k
c=k
Next we plug it in,[ -4k +- sqrt(16k^2-20k)]/10, now I cannot give the answer because that is not letting you learn, so you must find the value of 16k^2 - 20k that is greater than 0, > 0. Solve the question and good luck 👍
