The equation y = -16t^2 + 28t + 144 describes the height (in feet) of a ball tossed up in the air at 28 feet per second from a height of 144 feet from the ground. In how many seconds will the ball reach a height of 150 feet? Round your answer to the nearest tenth of a second.
+36916 150 = h
150 = -16t^2 + 28t + 144
-16t^2 + 28t - 6 = 0 Quadratic formula shows t = 1/4 second ( on the wy up) and 1.5 seconds (on the way down)
+36916 150 = h
150 = -16t^2 + 28t + 144
-16t^2 + 28t - 6 = 0 Quadratic formula shows t = 1/4 second ( on the wy up) and 1.5 seconds (on the way down)
