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The equation y = -16t^2 + 28t + 144 describes the height (in feet) of a ball tossed up in the air at 28 feet per second from a height of 144 feet from the ground. In how many seconds will the ball reach a height of 150 feet?  Round your answer to the nearest tenth of a second.

 Jun 3, 2021

Best Answer 

 #1
avatar+32592 
+2

150 = h

 

150 = -16t^2 + 28t + 144

-16t^2 + 28t - 6 = 0    Quadratic formula shows   t =    1/4  second  ( on the wy up)   and     1.5 seconds (on the way down)

 Jun 3, 2021
 #1
avatar+32592 
+2
Best Answer

150 = h

 

150 = -16t^2 + 28t + 144

-16t^2 + 28t - 6 = 0    Quadratic formula shows   t =    1/4  second  ( on the wy up)   and     1.5 seconds (on the way down)

ElectricPavlov Jun 3, 2021

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