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The equation y = -4.2t^2 + 42t + 18.9 describes the height (in meters) of a ball tossed up in the air at 42 meters per second from a height of 18.9 meters from the ground, as a function of time in seconds. In how many seconds will the ball reach maximum height?

 Jul 5, 2021
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-4.2t +  42t  + 18.9

 

Time  to reach  max  ht =      -42  /  (2 * -4.2)   =  -42 / -8.4  =  5  sec

 

 

cool cool cool

 Jul 5, 2021

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