What real value of t produces the smallest value of the quadratic t^2 -9t - 36 + t^2 - t + 14?
+2196
What real value of t produces the smallest value of the quadratic t^2 -9t - 36 + t^2 - t + 14?
t2 – 9t – 36 + t2 – t + 14
This is a parabola that opens upward
so the smallest value is at the vertex. 2t2 – 10t – 22
Set the first derivitive equal to zero. 4t – 10 = 0
4t = 10
t = 2.5
The question doesn't ask for it, but at t = 2.5 the value of the quadratic is –34.5.
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