Solve the inequality x^2 - 3x + 2 < 0.
(x-2)(x-1) <0 ONE of these must be less than zero if EITHER is = 0 or if both are negative then the equation is not true
(x-2) < 0 (x-1)<0
x <2 x < 1 so between 1 and 2 (non-inclusive) this is true : (1,2)
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