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Three runners, Dirk, Edith, and Foley all start at the same time for a $24$ km race, and each of them runs at a constant speed. When Dirk finishes the race, Edith is $10$ km behind, and Foley is $15$ km behind.  When Edith finishes the race, how far behind is Foley, in km?

 Jan 27, 2024
 #1
avatar+129883 
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When  Dirk finishes, Edith has run 14km  and Foley has run 9 km

 

So   Folley  runs  9/14 of Edith's distance at any time

 

So....when  Edith finishes, Foley has run   24  (9/14)  = 108/7  km

 

So....he is  24 - 108/7  = 60/7 ≈ 8.57 km behind

 

cool cool cool

 Jan 28, 2024

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