Simplify (1+3+5+...+199+201+203)/(2+4+6+...+200+202+204).
Sum of the first n odd integers = n^2
Sum of the first n even integers = n (n + 1)
We have (203 - 1) / 2 + 1 = 102 odd integers and (204 - 2) / 2 + 1 = 102 even integers
So.....this simplifies to
(102)^2 102
________ = _____
102 * 103 103