+0  
 
0
61
2
avatar

Suppose a, b, c, and d are real numbers which satisfy the system of equations

a + 2b + 3c + 4d = 10

4a + b + 2c + 3d = 4

3a + 4b + c + 2d = -10

2a + 3b + 4c + d = −4.

Find a + b + c + d.

 Nov 3, 2021
 #1
avatar+32772 
+2

Hint: Add up the four equations.

 Nov 3, 2021
 #2
avatar+391 
0

Hi Guest,

 

I used wolframalpha,

 

a = - 3/2

b = - 7/2 

c = 3/2

d = 7/2

 

Now add these values together.

 

Straight

 Nov 3, 2021

5 Online Users