Suppose a, b, c, and d are real numbers which satisfy the system of equations
a + 2b + 3c + 4d = 10
4a + b + 2c + 3d = 4
3a + 4b + c + 2d = -10
2a + 3b + 4c + d = −4.
Find a + b + c + d.
Hint: Add up the four equations.
Hi Guest,
I used wolframalpha,
a = - 3/2
b = - 7/2
c = 3/2
d = 7/2
Now add these values together.
Straight
