+73 Part 1
A photograph has an area of 24 square inches and the length is 2 inches more than the width. Find the length and width of the photograph.
If x represents the width of the photograph, select all of the equations that could be used to solve this problem.
x(2x) = 24
x(x + 2) = 24
(x + 2)(x) = 24
2(x) + 2(x + 2) = 24
Part 2
Find the dimensions of the photograph.
width = ______ inches
length = ______ inches
The second and third equations are essentially the exact same, so those are the equation(s) you want.
Now you need to solve for x to get your width.
x(x+2)=24
x^2 + 2x = 24
x^2 +2x - 24 = 0
Solving for x using the quadratic equation
(-2 (+ or - ) ((2^2)-4(1)(-24))^1/2)/(2(1)) Taking something to the power of 1/2 is the same as a square root
This gets you x= -4 or 6
In this case, -4 does not make sense because you can't have a negative length.
So x=6. Therefore your width is 6 inches. Since your length is 2 inches longer than the width, add 2, and you get 8 inches.
