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Find $\sin \angle ACB$.

 

Find $\sin \angle ABC$.

 

 Oct 26, 2023
 #1
avatar+36919 
+1

You can use the Law of sines :

sin (70) / 25  =  sin C / 26        then sin C = .97728     C = ARCSIN ( .97728 ) = 77.76 degrees 

Now, you should know there are 180 degrees in the sum of the interior angles of a triangle :

 

Then angle B = 180 - 70 - 77.76 = 32.236 degrees      the sin of which is .5334 

 Oct 26, 2023

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